tentukan himpunan penyelesaian persamaan nilai mutlak [6n+1]=1/2

6n+1=1/2
6n=1/2-1
6n=-1/2
n=-1/2 : 6
n= -1/12


6n+1=-1/2
6n=-1 1/2
n=-1 1/2 : 6
n=- 1/4

jadi, HP = {-1/12,-1/4}

-1/2 = 6n+1 = 1/2
-3/2 = 6n = -1/2
-3/12 = n = -1/12
-1/4 = n = -1/12
HP = {-1/4 , -1/12}