Matematika

Pertanyaan

Limit x mendekati 0 sin 2x per 3 - akar 2x + 9 =
A. 3
B. 1
C. 0
D. -3
E. -6

1 Jawaban

  • Lim sin2x / 3 - √2x + 9
    x→0

    Lim sin2x (3 + √2x + 9) / 9 - (2x + 9)
    x→0

    Lim sin2x (3 + √2x + 9) / 9 - 2x - 9
    x→0

    Lim sin2x (3 + √2x + 9) / -2x
    x→0

    = (-1) (3 + √2(0) + 9)

    = - (3 + √9)

    = - (3 + 3)

    = -6

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