integral sin^4x cos^3x dx adalah

Integral Fungsi Trigonometri.

∫ sin⁴ x cos³ x dx
= ∫ cos x cos² x sin⁴ x dx
= ∫ cos x (1 - sin² x) sin⁴ x dx
u = sin x
du / dx = cos x
= ∫ cos x (1 - u²) u⁴ du / cos x
= ∫ (u⁴ - u⁶) du
= 1/5 u⁵ - 1/7 u⁷ + C
= 1/5 sin⁵ x - 1/7 sin⁷ x + C
= 1/35 (7 sin⁵ x - 5 sin⁷ x) + C
= 1/35 [sin⁵ x (7 - 5 sin² x)] + C