Hitunglah perpangkatan berikut 8^(⁴/³) 9^(½) per 32^(-1) 27^(⅔)

Penyelesaian:

Ingat: a^m . a^n = a^m+n
a^m / a^n = a^m-n
(a^m)^n = a^mn

[tex] \frac{8^4/3 . 9^1/2}{32^-1 . 27^2/3} [/tex]
= [tex] \frac{(2^3)^4/3 . (3^2)^1/2}{(2^5)^-1 . (2^3)^2/3} [/tex]
= [tex] \frac{2^4 . 3}{2^-5 . 3^2} [/tex]
= [tex] \frac{2^9}{3} [/tex]
= [tex] \frac{512}{3} [/tex]