integral dengan batas atas 1 batas bawah a x(x+2) dx= 4/3 tentukan nilai a

Penyelesaian:

[tex] \int\limits^1_a {x(x+2)} \, dx [/tex]
= [tex] \int\limits^1_a {(x^2+2x)} \, dx [/tex]
= 1/3x³ + x² ] a -> 1 = 4/3
= (1/3(1)³ + (1)²) - (1/3a³ - a²) = 4/3
= 4/3 - 1/3a³ - a² = 4/3
-1/3a³ - a² = 0
a² (-1/3a - 1) = 0
a = 0  V a = -3