Tentukan titik didih dan titik beku larutan 0,1 M larutan urea ( kb air = 0,52 , kf air = 1,86 )

Δtf=kf.m
=1,86.0,1
=0.186°
tf (titik beku)larutan urea = 0-(0.186)
= -0,186° C

Δtb = kb.m
= 0,52.0.1
=0.052°
tb(titik didih) larutan urea = 100+0.052
=100,052°C