ka tolong bantu ya besok dikumpulin :(

•
|3 - 2x| < 4
-4 < 3 - 2x < 4
-4 - 3 < -2x < 4 - 3
-7 < -2x < 1
-7/-2 > x > 1/-2
-1/2 < x < 7/2

•
x/2 + 9 ≥ 9
x/2 + 9 ≥ 9
x/2 ≥ 0
x ≥ 0

Atau
x/2 + 9 ≤ -9
x/2 ≤ -18
x ≤ -36

•
|3x + 2| ≤ 5
-5 ≤ 3x + 2 ≤ 5
-7 ≤ 3x ≤ 3
-7/3 ≤ x ≤ 1
(prosesnya kyk no.1)

•
|x + 5| ≤ |1 - 9x|
(x + 5)² - (1 - 9x)² ≤ 0
➡ ingat rumus : a² - b² = (a - b)(a + b)
(-8x + 6)(10x + 4) ≤ 0
x = 3/4 ; x = -2/5

Nilai x yg memenuhi : x ≤ -2/5 atau x ≥ 3/4