Tolong selesaikan |4-x| = |3+2x|

|4 - x| = |3 + 2x|
4 - x = 3 + 2x
4 + 3 = 2x + x
7 = 3x
x = 7/3
4 - x = -(3 + 2x)
4 - x = -3 - 2x
4 - 3 = 2x - x
1 = x
x = 1

|4-x| = |3+2x|
|4-x|² = |3+2x|² => |x|²= x²
(4-x)² = (3+2x)²
(4-x)² - (3+2x)²=0 => a²-b²=(a+b)(a-b)=0
((4-x)+(3+2x))((4-x)-(3+2x))
(4-x+3+2x)(4-x-3-2x)
(x+7)(-3x+1)=0
x₁=x + 7=0
x₁= x= -7

x₂= -3x + 1=0
x₂= -3x= -1
x₂= x= -1/-3=1/3

HP={-7, 1/3}
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