TENTUKAN AKAR AKAR PERSAMAAN KUADRATNYA DI BAWAH INI. 1. X^2 - 4X + 4 = 0 2. 2X^2 - 6X = -6 3. 6X^2 - 3X = 0

1. X^2 - 4X + 4 = 0
(x-2)^2 = 0. X=2
2. 2X^2 - 6X = -6
2x^2 - 6x + 6 = 0
x^2 - 3x + 3 = 0
(x-1)(x-2) = 0 X=1 & 2
3. 6X^2 - 3X = 0
3x(2x-1) = 0. X=(1/2) & 3

Bab : Persamaan Kuadrat satu Variabel
Kelas : X SMA

1. x^2 - 4x + 4 = 0
(x - 2 ) ( x - 2) = 0
x - 2 = 0 => x = 2
x - 2 = 0 => x = 2

Hp = { 2 } hanya 1 diambil karena akar akarnya sejenis

2. 2x^2 - 6x + 6 = 0
----------------------------(:2)
=> x^2 - 3x + 3 = 0
Saya bingung sampai sini ...

3. 6x^2 - 3x = 0
3x (x - 3 ) = 0
3x = 0
x = 0

x - 3 =0
x = 3

Hp = { 0 , 3 }