Tolong di jawab yaaa

Nomer 1 Harua di gambar pake buku tulis
jadi gw jawabnya nomer 2 aja Yak



2) ELIMINASI
3x-5y =7 | x1 | 3x-5y =7 ]
x-3y =1 | x3 | 3x-9y =3 ]
_______-
4y = 4
y=1

3x-5y = 7 | x3 | 9x-15y = 21
x-3y = 1 |x5 | 5x-15y = 5
_______-
4x = 16
x= 4


Substitusi
x-3y = 1 >> x = 1 + 3 y ✓
3y = 1-x

3x-5y = 7
3 (1+3y) -5y = 7
3+9y-5y = 7
3+4y = 7
4y = 7-3
4y = 4
y = 1


x - 3y = 1
x - 3(1) = 1
x -3 = 1
x = 1+3
x =4