4|3x-7| = 16 Pake cara yaa

4|3x-7| = 16
|3x-7| = 4

3x-7= 4
3x = 11
x = 11/3
atau
3x-7 = -4
3x = 3
x = 1

Hp ={1,11/3}

4|3x-7| = 16
|3x-7|=16/4
|3x-7|=4
(3x-7)²=16
9x²-42x+49=16
9x²-42x+49-16=0
9x²-42x+33=0
3x²-14x+11=0
a=3
b=-14
c=11
rumus x1,2= (-b+-√(b²-4ac))dibagi 2a
=( 14+-√( 14²-(4x3x11) ) )/ (2x3)
=( 14+- √(196-132))/6
= (14+-√64)/6

x1=( 14+ 8)/6 =22/6= 11/3=3 2/3
x2= (14- 8)/6= 6/6=1