Kimia

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kimia no 2 dan 3 (dlm gambar)
kimia no 2 dan 3 (dlm gambar)

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1 Jawaban

  • 2. ΔTb = Tb'-Tb°
    Tb' = 0.042+100=100.042

    ΔTb = m.Kb
    =3.6/180×1000/250×0.52
    =0.042

    3. ΔTb = m.kb
    =18/180×1000/500×0.52
    =0.1

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