(21+62)-(4×12)=n-(3×5) (15×15)÷Π=(81÷9)+(64÷4)
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(21+62)-(4×12)=n-(3×5)
(15×15)÷Π=(81÷9)+(64÷4)
(15×15)÷Π=(81÷9)+(64÷4)
1 Jawaban
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1. Jawaban arwendym
1. (21+62)-(4x12) = n-(3x5)
83-48 = n-15
35 = n-15
n = 50
2. (15x15)/n = (81/9)+(64/4)
225/n = 9+16
225-25 = n
n = 200