tolong kasih tau gimana caranya?

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= [tex] \frac{4 \sqrt{2} }{2 \sqrt{6} - 3 \sqrt{8} } [/tex] x [tex] \frac{2 \sqrt{6} + 3 \sqrt{8} }{2 \sqrt{6} + 3 \sqrt{8}} [/tex]

= [tex] \frac{8 \sqrt{12} + 12 \sqrt{16} }{12 - 24} [/tex]

= [tex] \frac{16 \sqrt{3} + 48}{-12} [/tex]

= - [tex] \frac{4 \sqrt{3} + 12}{3} [/tex]