Mohon bantuannya untuk soal yang dilingkari

No 6 n 7 aja ya..

6•
a = √(2√(2√(2√(...
a² = 2√(2√(...
a² = 2a
a(a - 2) = 0
a = 2
√(2√(2√(... = 2

7•
a = 2 + 3/(2 + 3/(2 + ...
a = 2 + 3/a
a = (2a + 3)/a
a² - 2a + 3 = 0
(a - 3)(a + 1) = 0
a = 3 atau a = -1

Nilai yg mungkin
a = 3
2 + 3/(2 + 3/(2 + ... = 3