Tolong dibantu ya, pake caranya ya kakak²...

semoga membantu dan bermanfaat
2) a. [tex] \frac{3}{2-15}= \frac{3}{-13}=- \frac{3}{13} [/tex]
b. [tex] \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{3} - \sqrt{2} }= \frac{(\sqrt{2} + \sqrt{3} )}{( \sqrt{3} - \sqrt{2}) } . \frac{( \sqrt{3}+ \sqrt{2}) }{( \sqrt{3} + \sqrt{2}) }= \frac{2 \sqrt{6}+5 }{1}=2 \sqrt{6}+5 [/tex]

3.gunakan aturan [tex](a+b)(a-b)= a^{2} - b^{2} [/tex]
[tex](3 \sqrt{2}+2 \sqrt{3})(3 \sqrt{2}-2 \sqrt{3})=(3 \sqrt{2}) ^{2}-(2 \sqrt{3}) ^{2}=18-12=6 [/tex]