tentukan f'(x) jika dik a.f(x) = 2x^2 - 3x b. f(x) = 2 cos (3x - 1)

Bagian A
f(x) = 2x² - 3x
f'(x) = 2.2x^(2 - 1) - 3x^(1-1)
f'(x) = 4x - 3

Bagian B
f(x) = 2 cos (3x - 1)

u = 2 ------- v = cos (3x - 1)
u' = 0 ------ v' = 3 sin (3x - 1)

f'(x) = u'.v + u.v'
f'(x) = 0. cos (3x - 1) + 2. 3 sin (3x - 1)
f'(x) = 6 sin (3x - 1)

semoga berguna +_+