Matematika

Pertanyaan

cuma nomer6,7,8 aja ya, besok dikumpulin, tolong yaaa, pake cara
cuma nomer6,7,8 aja ya, besok dikumpulin, tolong yaaa, pake cara

2 Jawaban

  • semoga membantu yaa ^^
    Gambar lampiran jawaban idznizhahrina
  • 6.  (a⁸ : a⁶)³ = [tex] a^{(8-6)3} [/tex] = a⁶

    7. [tex] \frac{4^{2}}{2^{-2}a^{3}b^{-1}} = \frac{(2^{2})^{2}}{2^{-2}a^{3}b^{-1}} = \frac{2^{4}}{2^{-2}a^{3}b^{-1}} = \frac{2^{(4+2)}b^1}{a^{3}} = \frac{2^{6}b}{a^3} [/tex]

    8. [tex]( \frac{a^{3}b^{5}}{ab^{2}} )^{4} = ( a^{(3-1)}b^{(5-2)})^{4} = ( a^{2}b^{3})^{4} = a^{8}b^{12}[/tex]