tentukan penyelesaian dari a.x^2+x-6=0 b.x^2+12=7x c.3x^2+5x-2=0

(a).x^2+x-6=0
(x+3)(x-2)=0
x=-3  x=2
HP={-3,2}

(b). x^2-7x+12=0
(x-4)(x-3)=0
x=4  x=3
HP={3,4}

(c). 3x^2+5x-2=0
(3x-1)(x+2)=0
x=1/3  x=-2
HP={-2,1/3} 

a) x^2 + x - 6 = 0
(x + 3)(x - 2) = 0
x + 3 = 0 atau x - 2 = 0
x = -3 atau x = 2

b) x^2 + 12 = 7x
x^2 - 7x + 12 = 0
(x - 3)(x - 4) = 0
x - 3 = 0 atau x - 4 = 0
x = 3 atau x = 4

c) 3x^2 + 5x - 2 = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 atau x + 2 = 0
3x = 1 atau x = -2
x = 1/3