apakah hasil bilangan mutlak Dari [x-3]=[x+2]

|x-3|=|x+2|
(x-3)^2=(x+2)^2
x^2-6x+9=x^2+4x+4
-6x-4x=4-9
-10x=-5
x=-5/-10
x=1/2
HP={1/2}

|x - 3| = |x + 2|
(x - 3)² - (x + 2)² = 0
➡ a² - b² = (a + b)(a - b)
(2x - 1)(-5) = 0
x = 1/2

HP = {1/2}