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Materi : Bentuk Akar
Bahasan : Rasional Bentuk Akar
Jawaban : 5 + 2√6

Langkah - langkah :
[tex] \frac{ \sqrt{3} + \sqrt{2} } {\sqrt{3} - \sqrt{2} } \\ \\ = \frac{\sqrt{3} + \sqrt{2}. (\sqrt{3} + \sqrt{2})}{\sqrt{3} - \sqrt{2} . (\sqrt{3} + \sqrt{2})} \\ \\ Gunakan : (a - b)(a + b) = a^{2} - b^{2} \\ \\ = \frac{( \sqrt{3} + \sqrt{2} )^{2} }{1} \\ \\ = 3 + 2 \sqrt{6} + 2 \\ \\ = 5 + 2 \sqrt{6}[/tex]