Matematika

Pertanyaan

sebidang tanah berbentuk persegi panjang dgn lebar x+2m dn panjang x+7m keliling persegi panjang tersebut 54 cm tentukan
a.panjang dn lebar tanah
b.luas tanah

2 Jawaban

  • L = x + 2 m
    P = x + 7 m

    K = 2 (p+l)
    54 = 2 (x + 2 + x + 7)
    54 = 2 (2x+9)
    54 = 4x + 18
    -4x = 18 - 54
    -4x = -36
    4x = 36
    x = 9

    A. P = 9 + 7 = 16 m
    L = 9 + 2 = 11 m

    B. L = p x l
    L = 16 m x 11 m
    L = 176 m²
  • l = x + 2
    p = x + 7
    k = 2p + 2l
    54 = 2(p + l)
    54 = 2(x + 2 + x + 7)
    54 = 2(2x + 9)
    54 = 4x + 18
    54 - 18 = 4x
    36 = 4x
    x = 36/4 = 9
    a) p = x + 7 = 9 + 7 = 16m
    l = x + 2 = 9 + 2 = 11m
    b) L = p × l
    L = 16 × 11 = 176m²

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